Appendix L
761
centre of the beam, caused by the load en. In short, as B^
oc/ oc S, M! must equal M2, in order to cause the least stress
in the beam. Assuming the lettered dimensions to represent
PADDLE. FL.O/\T
BO,^H Fjuof.753.
1fe,__
<:/?/t/vr
J&0.754,
feet, and the load to be i Ib. per foot run, then the bending
moments are as follows:—
(i) Due to distributed load at b = —
(2; Due to distributed load at a - x =---------
(3 ) Due to concentrated load at E = x(a - K)
(See also Fig. 400.)
(2 x}2 x'2
(4) Due to distributed load at 2 x = ^-5— = :™
But (24-3) = Mj and (i) = M1
also (4) = M2
.-. (4)= (i),
and kv=
Again (4) == (2 -f 3)
(a - sc
a - oc)
l-b
or 2 b^ = dP
and b~
I H-
».= = '414 /